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09-05-2014, 03:58 PM | #16 |
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I found this question on another test of the same company
with no curved lines maybe u got instructors manual???? NICE
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09-05-2014, 04:00 PM | #17 |
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B B B B B B B B B B B B B B
Always pick B in a multiple choice test. |
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09-05-2014, 04:06 PM | #18 | |
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Quote:
****, been 5 years and a near total dump of the concepts from that awful class. |
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09-05-2014, 04:12 PM | #19 |
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****, no. Maybe you have to complete each by adding arrows to show the movement of electrons onto each carbon in the ring, and also show the movement of electrons back onto the nitrogen in the fourth, a la this one:
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09-05-2014, 04:19 PM | #20 | |
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Quote:
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09-05-2014, 06:01 PM | #21 |
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I have no idea. But I have a buddy that has a doctorate and some post doc work in chemistry. PM me if you want me to call him.
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09-05-2014, 06:06 PM | #22 |
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aniline
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09-05-2014, 06:18 PM | #23 |
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So in that first picture, if you moved the double bond to the amine, the nitrogen would have a negative charge, because it's going to have a double bond, plus 2 hydrogen, plus it's electron pair. nitrogen doesn't like that (octet rule). also the carbon that loses that double bond is going to be positively charged since it will be only bound to 2 carbons and a hydrogen and is missing a valence electron. It's been years since I've done something like that example. But you have a conjugated system.
The electron pair moves from the N to the carbon closest to it to form the double bond, and an electron pair moves from that carbon to the one adjacent to it. I'm a little confused by how they drew it though. but it's been a long time for me and we only went over ortho, para, and meta for one session here's a decent picture of what I mean basically the nitrogen has a partial positive charge and all of the carbons have a partial negative if that makes sense Last edited by DrunkBassGuitar; 09-05-2014 at 06:35 PM.. |
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09-05-2014, 06:18 PM | #24 |
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Four.
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09-05-2014, 06:22 PM | #25 |
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Two single bonds and two lone pairs on N
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09-05-2014, 06:25 PM | #26 |
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You dipwad, That's already answered . I jerk off friggin pigs and know that !
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09-05-2014, 06:40 PM | #27 |
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When you all get this sorted - I have a few Algebra II questions.
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09-05-2014, 06:47 PM | #28 |
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09-05-2014, 06:57 PM | #29 | |
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09-05-2014, 07:00 PM | #30 |
Now you've pissed me off!
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Ok, so moving the lone pair on the last benzene ring on the carbon with the negative formal charge to form a double bond in the upper left hand corner is correct, but my attempts for the other three were not.
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