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Old 07-13-2014, 10:32 PM   #37
beach tribe beach tribe is offline
Keep doubting J MFing Houston
 
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Join Date: May 2007
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Quote:
Originally Posted by mac459 View Post
To apply a sniper for a shot over 1.5 miles is basically useless..to see a target at that distance is hard enough but to apply an effective shot is nearly impossible..longest shot in history is 1.53 miles..to use a sniper over that distance is going to be very hard to do..the target can easily move out of the way..it takes 5.7 seconds for the .338 Lapua to reach its target at 2700 yards..the rifling in the barrel has to be perfect..the bullet has to fire exactly how it is designed..not going even 5fps slower..the amount of effect your MOA has at 1.5 miles is unreal..MOA is basically you have to shoot at an inch or less at 100 yards..so at 2700 yards or 1.5 miles the MOA is 27 inches..if you are off 1 inch at 100 yards it will be 27 inches off at 2700.. since a torso-sized target measures approximately 18 inches wide and 36-inches high..the 27-inch group is 9 inches wider than the target..but well within the 36-inch vertical area..roughly it could be said that looking at a one MOA group size there’s about a 70% chance of striking the target at 2700 yards..if the rifle were grouping better..say around 7/10th of an inch..or 0.7 MOA..its 2700-yard group would measure 18.9 inches..assuming mechanical perfection and a perfect shooter with no consideration for crosswinds..I am unaware of any scope made anywhere in the world with enough elevation to make a 2700-yard shot..even with a 500-yard zero the .338 will impact 5311 inches low at 2700 feet..since one MOA equals 27 inches at 2700 yards, this means a shooter needs 196 MOA of elevation to hit at that distance. (5311 inches divided by 27 = 196 MOA)..the the bullet has an effect called plunging..just like firing downhill..at extreme distances a bullet’s steep plunge reduces the relative size of a target..think of it this way..let’s say you’re firing at a target at 100 yards which measures 36 inches high by 18 inches wide..648 square inches.at 300 yards or less your bullet flies fairly flat..so the target offers its entire 648-square-inch frontal area for impact.but when firing at 2700 yards..the angle of your bullet’s arc becomes very steep..so that the impact area shrinks considerably..I’d say with the bullet plunging down at 45 degrees..in relative terms that 648 square inches has shrunk by nearly one-half..at such a long distance..even a mild wind might make that shot impossible..and traveling so far that bullet may have to pass through multiple winds of varying direction and velocity..but say there’s just one wind and it’s only 5 miles-per-hour..at 2700 yards a 5 MPH 90-degree crosswind requires 244 inches of right or left compensation..if you were to dial that on a windage knob that’s not too bad..only 9 MOA or 36 clicks on a ¼ MOA target knob..if you needed to fire faster and used the horizontal mil scale to hold right or left, you would hold exactly 2.5 mils..with all of that its just easier to drop in mortors or send in a platoon..I don't see a real world application where a sniper would be used for anything at any distance over 2700 yards in the near future
Which is why they use the EXACTO and pop targets from over 4 miles away w/o having to use UAV resources.
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